1 solutions
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0
C++ :
#include <iostream> using namespace std; long long f[10050]; int a[30]; int n,m; int main() { cin>>n>>m; for (int i=1;i<=n;i++) { cin>>a[i]; } f[0]=1; for (int i=1;i<=n;i++) { for (int j=a[i];j<=m;j++) { f[j]=f[j]+f[j-a[i]]; } } cout<<f[m]; return 0; }
- 1
Information
- ID
- 19001
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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