1 solutions
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0
C++ :
#include <iostream> #include <cstdio> #include <cstring> using namespace std; const int N = 10010; char ch[N]; int main() { string s; getline(cin , s); int l = s.size(); //strcmp相等为0,前一个大返回值大于0,里面可以放数组名字(因为是地址) if(strcmp(&s[l-3],"ing") == 0) l -= 3; else if(strcmp(&s[l-2],"er") == 0 || strcmp(&s[l-2],"ly") == 0) l -= 2; for (int i = 0; i < l; ++i) cout << s[i] ; return 0; }
- 1
Information
- ID
- 18918
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By