1 solutions
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0
C++ :
#include <iostream> #include <cstring> using namespace std; const int N = 10010; char ch[N]; int c[26]; int main() { string s; getline(cin , s); for (int i = 0; i < s.size(); ++i) { c[s[i] - 'a']++;//按s串顺序记录每一个字符出现的次数 } for (int i = 0; i < s.size(); ++i) { if(c[s[i] - 'a'] == 1){//按s串查找第一个值出现了一次的字符 cout << s[i]; return 0; } } cout << "no"; return 0; }
- 1
Information
- ID
- 18912
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By