1 solutions

  • 0
    @ 2025-11-5 18:32:05

    C++ :

    #include <iostream>
    #include <cstring>
    using namespace std;
    const int N = 10010;
    char ch[N];
    int c[26];
    int main()
    {
        string s;
        getline(cin , s);
        for (int i = 0; i < s.size(); ++i) {
            c[s[i] - 'a']++;//按s串顺序记录每一个字符出现的次数
        }
        for (int i = 0; i < s.size(); ++i) {
            if(c[s[i] - 'a'] == 1){//按s串查找第一个值出现了一次的字符
                cout << s[i];
                return 0;
            }
        }
        cout << "no";
    
        return 0;
    }
    
    • 1

    Information

    ID
    18912
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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