1 solutions

  • 0
    @ 2025-11-5 18:31:53

    C++ :

    #include <iostream>
    using namespace std;
    const int N = 110;
    int a[N][N];
    int main() {
        int n, m;
        cin >> n >> m;
        for (int i = 0; i < n; ++i)
            for (int j = 0; j < m; ++j)
                cin >> a[i][j];
        for (int i = 0; i < m; ++i) {
            for (int j = 0; j < n; ++j) {
                cout << a[n-1-j][i] << " ";
            }
            cout << endl;
        }
        return 0;
    }
    
    • 1

    Information

    ID
    18909
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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