1 solutions
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0
C++ :
#include <iostream> using namespace std; const int N = 110; int a[N][N]; int main() { int n, m; cin >> n >> m; for (int i = 0; i < n; ++i) for (int j = 0; j < m; ++j) cin >> a[i][j]; for (int i = 0; i < m; ++i) { for (int j = 0; j < n; ++j) { cout << a[n-1-j][i] << " "; } cout << endl; } return 0; }
- 1
Information
- ID
- 18909
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By