1 solutions
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0
C :
#include<stdio.h> int main() { int i,n,a[2000],b[2000],sum=0; scanf("%d",&n); for(i=0;i<n;i++) scanf("%d",&a[i]); for(i=0;i<n;i++) scanf("%d",&b[i]); for(i=0;i<n;i++) sum=sum+a[i]*b[i]; printf("%d\n",sum); return 0; }C++ :
#include<bits/stdc++.h> using namespace std; int a[1005],b[1005]; int main() { int n,sum=0; cin>>n; for(int i=1;i<=n;i++) { cin>>a[i]; } for(int i=1;i<=n;i++) { cin>>b[i]; } for(int i=1;i<=n;i++) { sum=sum+a[i]*b[i]; } cout<<sum; return 0; }Python :
# coding=utf-8 n = int(input()) a = list(map(int, input().split())) b = list(map(int, input().split())) result = sum([x*y for x, y in zip(a, b)]) print(result)
- 1
Information
- ID
- 18901
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By