1 solutions

  • 0
    @ 2025-11-5 18:30:53

    C++ :

    #include <iostream>	
    #include <cstdio>	
    using namespace std;
    int main()
    {
    	double a[10]={28.9,32.7,45.6,78,35,86.2,27.8,43,56,65};//价格存放 
    	double x,s=0;
    	for(int i=0;i<10;i++) 
    	{
    		cin>>x; //每次输入本数 
    		s+=a[i]*x;//对应本数乘对应价格 累加 
    	}
    	printf("%.1lf\n",s);//保留一位小数输出 
    	return 0;
    }
    
    
    • 1

    Information

    ID
    18900
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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