1 solutions
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0
C++ :
#include <iostream> #include <cstdio> using namespace std; int main() { double a[10]={28.9,32.7,45.6,78,35,86.2,27.8,43,56,65};//价格存放 double x,s=0; for(int i=0;i<10;i++) { cin>>x; //每次输入本数 s+=a[i]*x;//对应本数乘对应价格 累加 } printf("%.1lf\n",s);//保留一位小数输出 return 0; }
- 1
Information
- ID
- 18900
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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