1 solutions
-
0
C :
#include <stdio.h> int main() { double p, q; while(scanf("%lf%lf", &p, &q)!=EOF){ printf("%06lf\n", (p-q)/(p+q)); } return 0; }C++ :
#include <cstdio> #include <cstring> #include <cstdlib> int main(int argc, char **argv) { int p, q; while(scanf("%d%d", &p, &q) == 2) { printf("%.6f\n", 1.0 * (p - q) / (p + q)); } return 0; }
- 1
Information
- ID
- 18785
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By