1 solutions
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0
C++ :
#include <iostream> #include <cstdio> #include <cstdlib> #include <cmath> #include <algorithm> #include <climits> #include <cstring> #include <string> #include <set> #include <map> #include <queue> #include <stack> #include <vector> #include <list> #include <bitset> #define rep(i,m,n) for(i=m;i<=n;i++) #define rsp(it,s) for(set<int>::iterator it=s.begin();it!=s.end();it++) #define vi vector<int> #define pii pair<int,int> #define mod 1000000007 #define inf 0x3f3f3f3f #define pb push_back #define mp make_pair #define fi first #define se second #define ll long long #define pi acos(-1.0) const int maxn=1e6+10; const int dis[4][2]={{0,1},{-1,0},{0,-1},{1,0}}; using namespace std; ll gcd(ll p,ll q){return q==0?p:gcd(q,p%q);} ll qpow(ll p,ll q){ll f=1;while(q){if(q&1)f=f*p;p=p*p;q>>=1;}return f;} int n,m; struct node { double l,r,len; }p[maxn]; bool check(double now) { double t=0; for(int i=0;i<n;i++) { if(t+p[i].len/now>p[i].r)return false; else { t=max(t+p[i].len/now,p[i].l); } } return true; } int main() { int i,j,k,t; scanf("%d",&n); rep(i,0,n-1)scanf("%lf%lf%lf",&p[i].l,&p[i].r,&p[i].len); double l=0,r=1e10,ans; while(r-l>1e-5) { double mid=(l+r)/2; if(check(mid))ans=mid,r=mid; else l=mid; } printf("%.2f\n",ans); //system ("pause"); return 0; }
- 1
Information
- ID
- 18779
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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