1 solutions

  • 0
    @ 2025-11-5 18:06:03

    C++ :

    #include <iostream>
    #include <cstdio>
    #include <cstdlib>
    #include <cmath>
    #include <algorithm>
    #include <climits>
    #include <cstring>
    #include <string>
    #include <set>
    #include <map>
    #include <queue>
    #include <stack>
    #include <vector>
    #include <list>
    #include <bitset>
    #define rep(i,m,n) for(i=m;i<=n;i++)
    #define rsp(it,s) for(set<int>::iterator it=s.begin();it!=s.end();it++)
    #define vi vector<int>
    #define pii pair<int,int>
    #define mod 1000000007
    #define inf 0x3f3f3f3f
    #define pb push_back
    #define mp make_pair
    #define fi first
    #define se second
    #define ll long long
    #define pi acos(-1.0)
    const int maxn=1e6+10;
    const int dis[4][2]={{0,1},{-1,0},{0,-1},{1,0}};
    using namespace std;
    ll gcd(ll p,ll q){return q==0?p:gcd(q,p%q);}
    ll qpow(ll p,ll q){ll f=1;while(q){if(q&1)f=f*p;p=p*p;q>>=1;}return f;}
    int n,m;
    struct node
    {
        double l,r,len;
    }p[maxn];
    bool check(double now)
    {
        double t=0;
        for(int i=0;i<n;i++)
        {
            if(t+p[i].len/now>p[i].r)return false;
            else
            {
                t=max(t+p[i].len/now,p[i].l);
            }
        }
        return true;
    }
    int main()
    {
        int i,j,k,t;
        scanf("%d",&n);
        rep(i,0,n-1)scanf("%lf%lf%lf",&p[i].l,&p[i].r,&p[i].len);
        double l=0,r=1e10,ans;
        while(r-l>1e-5)
        {
            double mid=(l+r)/2;
            if(check(mid))ans=mid,r=mid;
            else l=mid;
        }
        printf("%.2f\n",ans);
        //system ("pause");
        return 0;
    }
    
    • 1

    Information

    ID
    18779
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By