1 solutions

  • 0
    @ 2025-11-5 18:01:07

    C :

    #include<stdio.h>
    int main()
    {
    	int n,i,a[31];
    	a[0]=1;
    	a[2]=3;
    	a[4]=11;
    	for(i=6;i<31;i+=2)
    		a[i]=a[i-2]*4-a[i-4];
    	while(scanf("%d",&n)!=EOF,n!=-1)
    	{
    		if(n%2==0)
    			printf("%d\n",a[n]);
    		else
    			printf("0\n");
    	}
    	return 0;
    }
    
    • 1

    Information

    ID
    18716
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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