C :
#include<stdio.h> int main() { int n,i,a[31]; a[0]=1; a[2]=3; a[4]=11; for(i=6;i<31;i+=2) a[i]=a[i-2]*4-a[i-4]; while(scanf("%d",&n)!=EOF,n!=-1) { if(n%2==0) printf("%d\n",a[n]); else printf("0\n"); } return 0; }
By signing up a 算道OJ universal account, you can submit code and join discussions in all online judging services provided by us.
Using your 算道OJ universal account