1 solutions
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0
C :
#include <stdio.h> main(){ int n,i,sum; while (1 == scanf("%d",&n) && n) { sum = n; for (i=2;i*i <= n;i++) { if (n%i == 0) { sum -= sum/i; } while (n%i == 0) n /= i; } if (n > 1) sum -= sum/n; printf("%d\n",sum); } }C++ :
#include <stdio.h> unsigned eulerFunc(unsigned n) { unsigned ans = 1; for (unsigned i = 2; i*i <= n; i++) { if (n % i == 0) { n /= i, ans *= (i-1); while (n % i == 0) n /= i, ans *= i;//把质数除去,巧妙变相分解质因子 } } if (n > 1) ans *= (n-1); return ans; } int main() { int n; while (scanf("%d", &n) && n !=0) { printf("%d\n", eulerFunc(n)); } return 0; }
- 1
Information
- ID
- 18687
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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