1 solutions

  • 0
    @ 2025-11-5 17:58:48

    C :

    #include <stdio.h>
    
    main(){
       int n,i,sum;
       while (1 == scanf("%d",&n) && n) {
          sum = n;
          for (i=2;i*i <= n;i++) {
             if (n%i == 0) {
                sum -= sum/i;
             }
             while (n%i == 0) n /= i;
          }
          if (n > 1) sum -= sum/n;
          printf("%d\n",sum);
       }
    }
    
    

    C++ :

    #include <stdio.h>
    unsigned eulerFunc(unsigned n)
    {
    	unsigned ans = 1;
    	for (unsigned i = 2; i*i <= n; i++)
    	{
    		if (n % i == 0)
    		{
    			n /= i, ans *= (i-1);
    			while (n % i == 0) n /= i, ans *= i;//把质数除去,巧妙变相分解质因子
    		}
    	}
    	if (n > 1) ans *= (n-1);
    	return ans;
    }
    int main()
    {
    	int n;
    	while (scanf("%d", &n) && n !=0)
    	{
    		printf("%d\n", eulerFunc(n));
    	}
    	return 0;
    }
    
    • 1

    Information

    ID
    18687
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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