1 solutions
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0
C++ :
#include<iostream> #include<algorithm> #include<cstdio> using namespace std; const int N = 10005; struct per{ int id,t; }; per a[N]; bool comp(per x,per y){ if (x.t!=y.t) return x.t<y.t; return x.id<y.id; } int main(){ int n; cin>>n; for (int i=1; i<=n; i++){ a[i].id=i; cin>>a[i].t; } sort(a+1,a+n+1,comp); for (int i=1; i<n; i++) cout<<a[i].id<<" "; cout<<a[n].id<<endl; double sum=0; for (int i=1,k=0; i<=n; i++){ k+=a[i].t; sum+=k; } printf("%.2lf\n",sum/n); return 0; }
- 1
Information
- ID
- 18653
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By