1 solutions
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0
C :
#include <stdio.h> long long int f[50]; int main() { f[1] = 0; f[2] = 1; f[3] = 2; for(int i = 4;i <= 50;++i) f[i] = f[i - 1] + f[i - 2]; int m; while(~scanf("%d",&m)) { printf("%lld\n",f[m]); } return 0; }C++ :
#include <stdio.h> long long int f[50]; int main() { f[1] = 0; f[2] = 1; f[3] = 2; for(int i = 4;i <= 50;++i) f[i] = f[i - 1] + f[i - 2]; int m; while(~scanf("%d",&m)) { printf("%lld\n",f[m]); } return 0; }
- 1
Information
- ID
- 18599
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By