1 solutions
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0
C :
#include <stdio.h> #include <math.h> int main () { int i; double s; s = 0; for(i=0; i<=100000; i++) { s+=pow(-1,i)/(2*i+1); } s=4*s; printf("%.1f",s); return 0; }Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub double sum = 0; int flag = 1; for (int i = 1; i <= 50; i++) { sum += 1.0 / (2*i-1) * flag; flag *= -1; } sum *= 4; System.out.printf("%.1f\n",sum); } }
- 1
Information
- ID
- 18563
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By