1 solutions

  • 0
    @ 2025-11-5 17:32:41

    C :

    #include <stdio.h>
    
    int main()
    {
    	double num1,num2;
    	
    	scanf("%lf %lf",&num1,&num2);
    	
    	printf("%.0lf+%.0lf=%.0lf\n",num1,num2,num1 + num2);
    	printf("%.0lf-%.0lf=%.0lf\n",num1,num2,num1 - num2);
    	printf("%.0lf*%.0lf=%.0lf\n",num1,num2,num1 * num2);
    	printf("%.0lf/%.0lf=%.2lf\n",num1,num2,num1 / num2);
    	printf("%.0lf div %.0lf=%d\n",num1,num2,(int)num1 / (int)num2);
    	printf("%.0lf mod %.0lf=%d\n",num1,num2,(int)num1 % (int)num2);
    	return 0; 
    }
    

    C++ :

    #include<cstdio>
    
    using namespace std;
    	
    int main()
    {
    	int a,b;
    	scanf("%d%d",&a,&b);
    	printf("%d+%d=%d\n",a,b,a+b);
    	printf("%d-%d=%d\n",a,b,a-b);
    	printf("%d*%d=%d\n",a,b,a*b);
    	printf("%d/%d=%.2lf\n",a,b,a/b*1.0);	
    	printf("%d div %d=%d\n",a,b,a/b);
    	printf("%d mod %d=%d\n",a,b,a%b);
    	return 0;
    }
    
    • 1

    Information

    ID
    18543
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    (None)
    Tags
    # Submissions
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