1 solutions
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0
C :
#include <stdio.h> int a[1001] = {0,1,1}; int main(void) { int i, n; do scanf("%d", &n); while(!(n >= 1 && n <= 1000)); for(i = 3; i <= n; i ++) a[i] = a[i-2] + a[i-1]; printf("%d", a[n]); return 0; }C++ :
#include<cstdio> using namespace std; int a[110]; int main() { int i,n; scanf("%d",&n); a[1]=1; a[2]=1; for(i=3;i<=n;i++) { a[i]=a[i-1]+a[i-2]; } printf("%d\n",a[n]); return 0; }Pascal :
var i,j,k,m,n:longint; a:array[1..10000]of longint; begin readln(n); a[1]:=1; a[2]:=1; for i:=3 to n do a[i]:=a[i-1]+a[i-2]; write(a[n]); end.
- 1
Information
- ID
- 18533
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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