1 solutions
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0
C++ :
#include <cstdio> #include <cstring> #include <cstdlib> #include <iostream> #include <algorithm> #include <stack> #include <queue> #include <cmath> #include <string> #include <set> #include <map> #define maxn 0 using namespace std ; char ans[5] ; char lj[5] ; char my[5] ; int main () { int n, m ; int p, k ; int sum ; memset (ans, 0, sizeof(ans)) ; scanf ("%d%s", &n, ans) ; while (n--) { sum = 0 ; scanf ("%d\n", &m) ; while (m--) { memset (my, 0, sizeof(my)) ; memset (lj, 0, sizeof(lj)) ; scanf ("%s%d%d", my, &p, &k) ; my[3] = '\0' ; sum -= 2 * k ; if (p == 1) { if (my[0] == ans[0] && my[1] == ans[1] && my[2] == ans[2]) sum += 1040 * k ; } else if (p == 3) { strcpy (lj, my) ; sort (lj, lj+3) ; while (next_permutation (lj, lj+3)) { if (!strcmp (ans, lj)) { sum += 346 * k ; break ; } } } else if (p == 6) { strcpy (lj, my) ; sort (lj, lj+3) ; while (next_permutation (lj, lj+3)) { if (!strcmp (ans, lj)) { sum += 173 * k ; break ; } } } } if (sum > 0) printf ("赚了%d元\n", sum) ; else if (sum == 0) printf ("您浪费卖彩票的一张纸\n") ; else printf ("您为了福利事业贡献%d元\n", -sum) ; } return 0 ; }
- 1
Information
- ID
- 18494
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By