1 solutions
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0
C++ :
#include<iostream> #include<cmath> #include<iomanip> using namespace std; int aff(int n) //求因子和 { int t=sqrt(n),sum=1; for (int i=2; i<=t; i++) if (n%i==0) sum+=i+n/i; if (n==t*t) sum-=t; return sum; } int main() { int n,flag=0; cin>>n; for (int i=2; i<=n; i++) { int a=aff(i); if (i!=a && i==aff(a)) { cout<<i<<" "<<a<<endl; flag=1; break; } } if (!flag) cout<<"nothing"<<endl; return 0; }
- 1
Information
- ID
- 18429
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
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- 0
- Accepted
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