1 solutions

  • 0
    @ 2025-11-5 17:26:08

    C++ :

    #include<iostream>
    #include<cmath>
    #include<iomanip>
    using namespace std;
    int aff(int n)	//求因子和
    {
    	int t=sqrt(n),sum=1;
    	for (int i=2; i<=t; i++)
    		if (n%i==0) sum+=i+n/i;
    	if (n==t*t) sum-=t;
    	return sum;
    }
    int main()
    {
    	int n,flag=0;
    	cin>>n;
    	for (int i=2; i<=n; i++)
    	{
    		int a=aff(i);
    		if (i!=a && i==aff(a))
    		{
    			cout<<i<<" "<<a<<endl;
    			flag=1;
    			break;
    		}
    	}
    	if (!flag) cout<<"nothing"<<endl;
    	return 0;
    }
    
    • 1

    Information

    ID
    18429
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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