1 solutions

  • 0
    @ 2025-11-5 17:23:59

    C :

    #include <stdio.h>
    #include <string.h>
    
    void mystrrev(char string[]);
    
    int main()
    {
    	char string[100];
    	scanf("%[^\n]s",&string);
    	mystrrev(string);
    	
    	return 0;
    } 
    
    void mystrrev(char string[])
    {
    	int n = strlen(string);
    	int i;
    	for( i=n-1; i>=0; i-- ){
    		printf("%c",string[i]);
    	} 
    }
    

    C++ :

    #include<iostream>
    #include<string.h>
    using namespace std;
    void mystrrev(char string[]){
    	int i;
    	for(i=strlen(string)-1;i>=0;i--){
    		cout<<string[i];
    	}
    }
    main(){
    	char string[101];
    	cin.getline(string,101);
    	mystrrev(string);
    	return 0;
    }
    

    Pascal :

    var st:string;
        i:longint;
    begin
      readln(st);
      for i:=length(st) downto 1 do
      write(st[i]);
    end.
    
    • 1

    C++字符串作业2:编写字符串反转函数mystrrev

    Information

    ID
    18385
    Time
    1000ms
    Memory
    32MiB
    Difficulty
    (None)
    Tags
    # Submissions
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