C :

//现有n块砖，要由n人一次搬完，假定男人一次可以搬4块，女人一次可以搬3块，两个小孩搬1块
#include <stdio.h>

int main()
{
	int n;
	scanf("%d",&n);
	int men;
	int woman;
	int children;
	int flag = 0; 
	for( men=1; men<=n/4; men++ ){
		for( woman=1;woman<=n/3; woman++ ){
			for( children=2; children<=2*n; children+=2 ){
				if( men+woman+children==n&&men*4+woman*3+children/2==n ){
					printf("men%d\nwomen%d\nchildren%d\n",men,woman,children);
					flag = 1;
				}
			}
		}
	} 
	
	if( flag != 1 ){
		printf("no result!");
	}
	return 0;
}

C++ :

#include <iostream>
using namespace std;
int main(){
	int x,y,z,n,c=0;
	cin>>n;
	for(x=1;x<n;x++){
	 for(y=1;y<n;y++){
	  for(z=1;z<n;z++){
	    if(((double)n==4*(double)x+3*(double)y+(double)z/2)&&(n==x+y+z)){
	    	cout<<"men"<<x<<endl;
	    	cout<<"women"<<y<<endl;
	    	cout<<"children"<<z<<endl;
	    	c=1;
		}
	  }
     }
    }
    if(c==0){
    cout<<"no result!";
    }
return 0;	
}