1 solutions

  • 0
    @ 2025-11-5 17:20:48

    C :

    #include <stdio.h>
    int main()
    {
    	printf("10\n");
    	return 0;
    }
    

    C++ :

    #include <iostream>
    using namespace std;
    
    int main()
    {
    	int y, m = 10, d = 1, count = 0;
    	for(y=1949; y<=2015; y++)
    		if((d+2*m+3*(m+1)/5+y+y/4-y/100+y/400+1)%7 == 0) count++;
    	cout<<count<<endl;
    	return 0;
    }
    
    • 1

    Information

    ID
    18325
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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