1 solutions

  • 0
    @ 2025-11-5 17:19:48

    C :

    #include <stdio.h>
    
    int main()
    {
    	int t;
    	int a, b, ra, rb;
    	int sum, rsum;
    	scanf("%d", &t);
    
    	while (t--)
    	{
    		scanf("%d %d", &a, &b);
    		rsum = ra = rb = 0;
    		while (a)
    		{
    			ra = ra * 10 + a % 10;
    			a /= 10;
    		}
    
    		while (b)
    		{
    			rb = rb * 10 + b % 10;
    			b /= 10;
    		}
    		
    		sum = ra + rb;
    
    		while (sum)
    		{
    			rsum = rsum * 10 + sum % 10;
    			sum /= 10;
    		}
    
    		printf("%d\n", rsum);
    	}
    	return 0;
    }
    

    C++ :

    #include<iostream>
    #include<cmath>
    using namespace std;
    
    int change(int n)
    {   int m=n,s=0,t=1;
        while(n)
        {   n/=10;
            t++;
        }
        while(m)
        {   s=s+m%10*(int)pow(10.0,t-2);
            m/=10;
      t--;
        }
    return s;
    }   
    int main()
    {
        int n,s,a,b;
        cin>>n;
        while(n--)
        {   cin>>a>>b;
            s=change(a)+change(b);
            cout<<change(s)<<endl;
        }
    return 0;
    }
    
    • 1

    Information

    ID
    18305
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By