1 solutions
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0
C++ :
#include<stdio.h> int main() { int n,v,t,temp,ans; double tt; while( scanf("%d", &n) && n ) { ans=1<<30; while(n--) { scanf("%d%d", &v, &t); if( t>=0 ) { tt = (4.5*3600/v);//计算到达终点所需时间 if( tt-(int)tt>0 ) tt++;//秒数应取整 temp=tt+t;//计算到达时间 if( ans>temp ) ans=temp; } } printf("%d\n",ans); } return 0; }
- 1
Information
- ID
- 18299
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By