1 solutions
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0
C :
#include<stdio.h> int main() { int i,j; for (i=1;i<9;i++) for(j=1;j<9;j++) { if((i*10+3) * 6528 == (3*10+j) * 8256) printf("%d %d\n",i,j); } return 0; }C++ :
#include <cstdio> #include <iostream> using namespace std ; int main() { for(int i = 1 ;i<=9 ;i++) { for(int j = 1 ;j<=9 ;j++) { if((i*10+3)*6528 == (30+j)*8256) printf("%d %d\n",i,j) ; } } }
- 1
Information
- ID
- 18294
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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