1 solutions
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0
C++ :
#include<iostream> using namespace std; int main() { int i=35,j=94,a=0,b=0; b=(j-2*i)/2; a=i-b; cout<<a<<' '<<b; return 0; }Pascal :
program p2680; var i,j:longint; begin for i:=1 to 35 do for j:=1 to 35 do begin if (i+j=35) and (2*i+4*j=94) then writeln(i,' ',j);; end; end.Java :
import java.util.Scanner; public class Main{ public static void main(String [] args){ // 设x 为鸡的个数,y 为兔子的个数 // x+y=35; // 2*x+4*y=94; for(int x=0;x<=35;x++){ int y=35-x; if(2*x+4*y==94){ System.out.printf("%d %d\n",x,y); } } } }
- 1
Information
- ID
- 18235
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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