1 solutions

  • 0
    @ 2025-11-5 17:15:09

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
        int i=35,j=94,a=0,b=0;
        b=(j-2*i)/2;
        a=i-b;
        cout<<a<<' '<<b;
        return 0;
    }
    

    Pascal :

    program p2680;
    var
      i,j:longint;
    begin
      for i:=1 to 35 do
      for j:=1 to 35 do
        begin
          if (i+j=35) and (2*i+4*j=94) then
            writeln(i,' ',j);;
        end;
    end.
    

    Java :

    import java.util.Scanner;
    public class Main{
        public static void main(String [] args){
            // 设x 为鸡的个数,y 为兔子的个数
            // x+y=35;
            // 2*x+4*y=94;
            for(int x=0;x<=35;x++){
                int y=35-x;
                if(2*x+4*y==94){
                    System.out.printf("%d %d\n",x,y);
                }
            }
        }
    }
    
    
    • 1

    Information

    ID
    18235
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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