1 solutions
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0
C++ :
#include <bits/stdc++.h> #define LL long long using namespace std; void f(LL x) { for (LL i = 2; i <= x / i; i ++) { while (x % i == 0) { cout << " " << i << endl; x /= i; } } if (x > 1) cout << " " << x << endl; cout << endl; } int main() { LL n; while (cin >> n && n >= 0) { f(n); } return 0; }
- 1
Information
- ID
- 18195
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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