1 solutions

  • 0
    @ 2025-11-5 17:07:19

    C :

    #include <stdio.h>
    #include <math.h>
    #include <string.h>
    #include <stdlib.h>
    #include <time.h>
    #define N 10
    int main()
    {
       // freopen("in","r",stdin);
      //  freopen("out","w",stdout);
    
      int max,min,i,cnt=0;
        long  n;
    	float sum,ave;
      while(scanf("%ld",&n)!=EOF)
      {
    	max=n%10;
    	min=n%10;
    	sum=0;
    	cnt=0;
    			while (n) {
    				i=n%10;
    				sum+=i;
    				if(max<i)
    					max=i;
    				if(min>i)
    					min=i;
    				n/= 10;
    				cnt++;
    			}
    		   ave=sum/cnt;
    			printf("%.2f %d %d\n",ave,max,min);
      }
    
    
      return 0;
    }
    
    

    C++ :

    #include<stdio.h>
    int main()
    {
    	int a[10],i,k,min;
    	long int n;
    	float sum,ave;
    	while(scanf("%d",&n)!=EOF)
    	{
    		i=0,sum=0;
    		while(n>0)
    		{
    			a[i]=n%10;
    			n=n/10;
    			i++;
    		}
    		min=a[0];
    		for(k=0;k<i;k++)
    		{
    			sum=sum+a[k];
    			if(min>=a[k])
    				min=a[k];
    
    		}
    		ave=sum*1.00/i;
    		printf("%.2f %d\n",ave,min);
    
    	}
                           return 0;
    }
    
    • 1

    Information

    ID
    18188
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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