1 solutions

  • 0
    @ 2025-11-5 17:00:25

    C :

    #include<stdio.h>
    int main()
    {
        int m,i,j,n,b;
        while(~scanf("%d",&n))
        {
            int a[1010]={0};
            m=0;
            b=1;
            for(j=1;;m++)
            {
                if(a[j]==1)
                    break;
                else
                {
                    a[j]=1;
                    j=j+m+1;
                    if(j>n)
                        j=j%n;
                    if(j==0)
                        j=1;
                }
            }
            for(i=1; i<=n; i++)
                if(a[i]==0)
                {
                    b=0;
                    break;
                }
            if(b==0)
                printf("NO\n");
            else
                printf("YES\n");
        }
        return 0;
    }
    
    

    C++ :

    #include <iostream>
    #include <cstdio>
    using namespace std;
    int a[1000];
    int main()
    {
        int n;
        while(~scanf("%d", &n))
        {
            int i,sum=0;
            for(i=1; i<=n; i++)
            {
                sum+=i;
            }
            a[0]=1;
            a[1]=2;
            for(i=2; i<n; i++)
            {
                a[i]=(a[i-1]+(i-1))%n+1;
    
            }
            int sum1=0;
            for(i=0; i<n; i++)
            {
                sum1+=a[i];
            }
    
            if(sum==sum1)
    
                cout<<"YES"<<endl;
    
            else
                cout<<"NO"<<endl;
        }
        return 0;
    }
    
    
    • 1

    Information

    ID
    18140
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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