1 solutions
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0
C :
#include<stdio.h> #include<string.h> int main() { char arr[80];int len,i; gets(arr); len=strlen(arr); for (i=len-1;i>=0;i--) { printf("%c",arr[i]); } putchar('\n'); return 0; }C++ :
#include<stdio.h> int main(void) { char st[100]; int i,j,num=0; char c,k,m; gets(st); for(i=0;c=st[i]!='\0';i++) for(j=i+1;k=st[j]!='\0';j++) { m=st[i]; st[i]=st[j]; st[j]=m; } printf("%s\n",st); return 0; }
- 1
Information
- ID
- 18097
- Time
- 1000ms
- Memory
- 12MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By