1 solutions
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0
C :
# include <stdio.h> #define p 3.1415 int main() { float r,s,l; while(scanf("%f",&r)!=EOF) { printf("%.2f %.2f\n",2*r*p,r*r*p); } return 0; }C++ :
#include <stdio.h> #include <math.h> #include <stdlib.h> #include <time.h> int main() { // freopen("in","r",stdin); // freopen("out","w",stdout); float a; while(scanf("%f",&a)!=EOF) { printf("%.2f %.2f\n",3.1415*2*a,3.1415*a*a); } return 0; }
- 1
Information
- ID
- 18092
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By