1 solutions

  • 0
    @ 2025-11-5 16:58:00

    C :

    # include <stdio.h>
    #define p 3.1415
    int main()
    {
    	float r,s,l;
    	while(scanf("%f",&r)!=EOF)
    	{
    		printf("%.2f %.2f\n",2*r*p,r*r*p);
    	}
    	return 0;
    } 
    

    C++ :

    #include <stdio.h>
    #include <math.h>
    #include <stdlib.h>
    #include <time.h>
    int main()
    {
      //  freopen("in","r",stdin);
      //  freopen("out","w",stdout);
    
        float a;
    
        while(scanf("%f",&a)!=EOF)
        {
    
    
           printf("%.2f %.2f\n",3.1415*2*a,3.1415*a*a);
        }
      return 0;
    }
    
    
    • 1

    Information

    ID
    18092
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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