1 solutions

  • 0
    @ 2025-11-5 16:56:08

    C :

    # include<stdio.h>
    int main()
    {
    	int a[2][2],b[2][2];
    	int m,n;
    	int i,j;
    	for(i=0;i<=1;i++)
    	{
    		for(j=0;j<=1;j++)
    		{
    			scanf("%d",&a[i][j]);
    		}
    	}
    	for(i=0;i<=1;i++)
    	{
    		for(j=0;j<=1;j++)
    		{
    			scanf("%d",&b[i][j]);
    		}
    	}
    	m = a[0][0]*a[1][1]-a[0][1]*a[1][0];
    	n = b[0][0]*b[1][1]-b[0][1]*b[1][0];
    	printf("%d\n",m+n);
    
    
    }
    
    • 1

    Information

    ID
    18090
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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