1 solutions
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0
C :
#include <stdio.h> int main() { long long n; scanf("%lld", &n); printf("%lld", (1+n) * n / 2); return 0; }C++ :
#include<stdio.h> #include<string.h> #include<stdlib.h> #include<math.h> long long f(long n) { long long sum=((1+n)*n)/2; return sum; } int main() { long s=0,m; while(scanf("%ld",&m)!=EOF) { printf("%ld\n",f(m)); } return 0; }Java :
import java.util.Scanner; public class Main { static Scanner sc = new Scanner(System.in); public static void main(String[] args){ Long n = sc.nextLong(); System.out.println((n*n-n)/2+n); } }
- 1
Information
- ID
- 18057
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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