1 solutions

  • 0
    @ 2025-11-5 16:54:21

    C :

    #include <stdio.h>
    int main()
    {
        long long n;
        scanf("%lld", &n);
        printf("%lld", (1+n) * n / 2);
        return 0;
    }
    

    C++ :

    #include<stdio.h>
    #include<string.h>
    #include<stdlib.h>
    #include<math.h>
    long  long f(long n) 
    {
    long  long sum=((1+n)*n)/2;
    return sum;
    
    }
    int main()
    {
    
    long s=0,m;
    
    	while(scanf("%ld",&m)!=EOF)
    	{
    
    
    printf("%ld\n",f(m));
    
    	}
    
    
    return 0;
    
    }
    

    Java :

    import java.util.Scanner;
    
    
    public class Main {
    	static Scanner sc = new Scanner(System.in);
    	public static void main(String[] args){
    		Long n = sc.nextLong();
    		System.out.println((n*n-n)/2+n);
    	}
    }
    
    • 1

    Information

    ID
    18057
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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