1 solutions
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0
C :
#include<stdio.h> #include<math.h> int main() { int t,n,i=0; float a,b; scanf("%d",&t); while(i<t) { scanf("%d",&n); a=pow(1.01,n); b=pow(0.99,n); printf("%.2f\n%.2f\n",b,a); i++; } return 0; }C++ :
#include<cstdio> #include<iostream> using namespace std; int main() { int i,j,k; int t,n,m; float ans_1,ans_2; scanf("%d",&t); while(t--) { ans_1=1.0; ans_2=1.0; scanf("%d",&n); for(i=1;i<=n;i++) { ans_1*=1.01; ans_2*=0.99; } printf("%.2f\n%.2f\n",ans_2,ans_1); } return 0; }
- 1
Information
- ID
- 18014
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By