1 solutions
-
0
C :
#include<stdio.h> int main(){ int a[101]; int n,m,i,mul,q; while(scanf("%d%d",&n,&m)!=EOF){ a[0]=2; for(i=1;i<n;++i){ a[i]=a[i-1]+2; } q=0; while(1){ mul=0; if(m+m*q>=n){ for(i=m*q;i<n;++i){ mul+=a[i]; } printf("%d",mul/(n-m*q)); break; } else{ for(i=0+m*q;i<m+m*q;++i){ mul+=a[i]; }} q++; printf("%d ",mul/m); } printf("\n"); } return 0; }
- 1
Information
- ID
- 17869
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By