1 solutions

  • 0
    @ 2025-11-5 16:34:17

    C :

    #include<stdio.h>
    int main(){
    	int a[101];
    	int n,m,i,mul,q;
    	while(scanf("%d%d",&n,&m)!=EOF){
    		a[0]=2;
    		for(i=1;i<n;++i){
    			a[i]=a[i-1]+2;
    		}
    		q=0;
    		
    		while(1){
    			mul=0;
    			if(m+m*q>=n){
    				for(i=m*q;i<n;++i){
    					mul+=a[i];
    				}
    				printf("%d",mul/(n-m*q));
    				break;
    			}
    			else{
    		    for(i=0+m*q;i<m+m*q;++i){
    			   mul+=a[i];
    			}}
    		    q++;
    
    			printf("%d ",mul/m);
    		}
    		printf("\n");
    	}
    		return 0;
    	}
    
    
    • 1

    Information

    ID
    17869
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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