1 solutions
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0
C :
#include<stdio.h> int main() { double sum=0,num,i,j; int n; scanf("%d",&n); for (i=n;i>=1;i--) { for(j=i,num=1;j>=1;j--) num*=j; sum+=num; } printf("%.0lf\n",sum); return 0; }C++ :
#include<iostream> #include<cstdio> using namespace std; int main() { int n; cin>>n; double t=1,sum=0; for (int i=1; i<=n; i++) { t*=i; sum+=t; } printf("%.0lf\n",sum); return 0; }
- 1
Information
- ID
- 17862
- Time
- 1000ms
- Memory
- 12MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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