1 solutions

  • 0
    @ 2025-11-5 16:33:55

    C :

    #include<stdio.h>
    int main()
    {
    	double sum=0,num,i,j;
    	int n;
    	scanf("%d",&n);
    	for (i=n;i>=1;i--)
    	{
    		for(j=i,num=1;j>=1;j--)
    			num*=j;
    		sum+=num;
    	}
    	printf("%.0lf\n",sum);
    	return 0;
    }
    

    C++ :

    #include<iostream>
    #include<cstdio>
    using namespace std;
    int main()
    {
    	int n;
    	cin>>n;
    	double t=1,sum=0;
    	for (int i=1; i<=n; i++)
    	{
    		t*=i;
    		sum+=t;
    	}
    	printf("%.0lf\n",sum);
    	return 0;
    }
    
    • 1

    Information

    ID
    17862
    Time
    1000ms
    Memory
    12MiB
    Difficulty
    (None)
    Tags
    # Submissions
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