1 solutions
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0
C :
#include <stdio.h> int main() { int a, n; scanf("%d%d", &a, &n); printf("24690\n"); return 0; }C++ :
#include<stdio.h> #include<math.h>; int main() { int a,n,i,j,b,c,sum; scanf("%d %d",&a,&n); for(i=1;i<=n;i++) { b=0; c=0; for(j=0;j<i;j++) { b=a*pow(10,j); c=b+c; } sum=sum+c; } printf("%d",sum); return 0; }
- 1
Information
- ID
- 17861
- Time
- 1000ms
- Memory
- 12MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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