1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; long long n,s,m,t,a[5000005]; int main() { cin>>n;a[1]=1; for(int i=2;i*i<=n;i++) if(a[i]==0) for(int j=2*i;j<=n;j+=i) a[j]++; for(int i=1;i<=n;i++) { m=sqrt(i); if(a[i]==0)t+=i; else { for(int j=2;j<=m;j++) if(i%j==0) { t+=j; break; } } } cout<<t; return 0; }
- 1
Information
- ID
- 17845
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By