1 solutions
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0
C++ :
#include<iostream> using namespace std; int a[1000]; int main() { int n; cin>>n; a[1]=1; a[2]=2; for(int i=3;i<=n;++i) a[i]=a[i-1]+a[i-2]; cout<<a[n]; }Pascal :
var n,i:longint; a:array[1..30] of longint; begin readln(n); a[1]:=1; a[2]:=2; for i:=3 to n do a[i]:=a[i-1]+a[i-2]; writeln(a[n]); end.
- 1
Information
- ID
- 17831
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By