1 solutions
-
0
C :
#include <stdio.h> int n, a, b, i; double t; int main(void) { scanf("%d", &n); for (i = 1; i <= n; i++) { scanf("%d %d", &a, &b); t += a * 0.1 * b; } printf("%.2f\n", t); return 0; }C++ :
#include<iostream> #include<cstdio> using namespace std; int main() { double n,a,b,s; cin>>n; s=0; for(int i=1;i<=n;i++) { cin>>a>>b; s=s+b/10*a; } printf("%.2lf",s); return 0; }Pascal :
var a,b,n,i,c,e:longint; d:real; begin c:=0; d:=0; e:=0; readln(n); for i:=1 to n do begin readln(a,b); c:=c+a; d:=d+a*(e+b/10); end; writeln(d:0:2); end.Python :
# coding=utf-8 n = int(input()) t = 0 for i in range(0, n) : s = input(). split() t = t + int(s[0]) * int(s[1]) / 10 print(format(t, ".2f"))
- 1
Information
- ID
- 17764
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By