1 solutions

  • 0
    @ 2025-11-5 16:24:11

    C++ :

    //可参考一下java的代码,比较简洁
    #include <iostream>
    #include <cstdio>
    using namespace std;
    int N;
    string A(int n)
    {
    	string s=""; 
        char t[4];
        int i;
    	for(i=1;i<=n;i++)
    	{ 
    		if(i>1)
    		{
    			if(i&1)	s+="+";
    			else s+="-";
    		}
    		s+="sin(";
    		sprintf(t,"%d",i);
    		s+=t;
    	} 
    	for(i=1;i<=n;i++)
    		s+=")";
    	return s;
    }
    string S(int n)
    {
    	char t[4];
    	sprintf(t,"%d",N+1-n);
    	if(n==1) return A(n)+"+"+t;
    	else return "("+S(n-1)+")"+A(n)+"+"+t;
    }
    int main()
    {
    	cin>>N;
        cout<<S(N);
    	return 0;
    }
    
    
    • 1

    Information

    ID
    17753
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By