1 solutions
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0
C :
#include <stdio.h> void main() { float x,y; scanf("%f",&x); if(x<=3) y=10; else if(x>3&&x<=5) y=10+(x-3)*1.8; else y=13.6+(x-5)*2.7; printf("%.2f\n",y); }C++ :
#include<iostream> #include<cstdio> using namespace std; int main() { double a; cin>>a; if (a<=3.0) printf("%.2lf",10.004); if (a>3.0&&a<=5.0) printf("%.2lf",10.00+((a-3.0)*1.8)); if (a>5.0) printf("%.2lf",13.6+((a-5.0)*2.7)); return 0; }Pascal :
var a,b:real; begin readln(a); if a<=3 then b:=10; if (a>3) and (a<=5) then b:=(a-3)*1.8+10; if a>5 then b:=2*1.8+(a-5)*2.7+10; writeln(b:0:2); end.Python :
# coding=utf-8 a = float(input()) if a <= 3 : t = 10 elif a <= 5 : t = 10 + (a - 3) * 1.8 else : t = 13.6 + (a - 5) * 2.7 print(format(t, ".2f"))
- 1
Information
- ID
- 17700
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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