1 solutions
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0
C :
#include<stdio.h> int main() { int i; double item,sum; item=1; sum=0; for(i=1;i<=30;++i){ item*=i; sum+=item; } printf("%.2e\n",sum); return 0; }C++ :
#include<iostream> #include<cstdio> using namespace std; int main() { double t=1,sum=0; for (int i=1; i<=30; i++) { t*=i; sum+=t; } printf("%.2e\n",sum); return 0; }Pascal :
begin write('2.74e+32');end.
- 1
Information
- ID
- 17592
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
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- # Submissions
- 0
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- 0
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