1 solutions
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0
C :
#include<stdio.h> int main() { int i,a,sum,b,d; double y; sum=0; a=0; d=0; for(i=1;i<=20;++i) { scanf("%d",&b); if(b>0) { sum+=b; d++; } if(b<0) a++; } y=(sum*0.1)/(d*0.1); printf("%d\n",a); printf("%.2f",y); return 0; }C++ :
#include<iostream> using namespace std; #define N 20 int main() { int a[N]; int c = 0, sum = 0; //average count float av = 0.0; for(int i=0; i<N; ++i){ cin >> a[i]; if(a[i] < 0){ ++c; }else{ sum += a[i]; } } av = (float)sum / (N - c); cout << c << endl; printf("%.2f", av); return 0; }
- 1
Information
- ID
- 17589
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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