1 solutions
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0
C :
#include<stdio.h> int main(){ int sum=0; int n,i; scanf("%d",&n); for(i=1;i<=n;++i){ sum+=3*i-1; } printf("%d",sum); return 0; }C++ :
#include<iostream> using namespace std; int main() { int n; cin >> n; int sum = 0; int j = 2; for(int i=0; i<n; ++i){ sum += j; j += 3; } cout << sum << endl; return 0; }
- 1
Information
- ID
- 17586
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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