1 solutions
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0
C :
#include<stdio.h> #define A 10 int main() { int fen[A]; int i,count,total; double c; total=0; count=0; for(i=0;i<A;++i) { scanf("%d",&fen[i]); total+=fen[i]; } c=(total*0.1); for(i=0;i<A;++i) { if(fen[i]>c) ++count; } printf("%d",count); return 0; }C++ :
#include<iostream> using namespace std; int main() { int a[11],sum=0,t=0; for (int i=1; i<=10; i++) { cin>>a[i]; sum+=a[i]; } double ave=sum/10; for (int i=1; i<=10; i++) if (a[i]>ave) t++; cout<<t<<endl; return 0; }
- 1
Information
- ID
- 17567
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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