1 solutions

  • 0
    @ 2025-11-5 16:10:53

    C :

    #include<stdio.h>
    void fun(int x,int *pp,int *n);
    int main()
    {
    	int x,pp[15],n,i;
    	scanf("%d",&x);
    	fun(x,pp,&n);
    	for(i=0;i<n;i++)
    	{
    		printf("%d",pp[i]);
    		if(i!=n-1)	printf(" ");
    	}
    	return 0;
    }
    
    void fun(int x,int *pp,int *n)
    {
    	int i,a=0,j=0;
    	*n=0;
    	for(i=1;a<=x;i++)
    	{
    		a = 2*i;
    		if(x%a==0)
    		{
    			*(pp+(j++))=a;
    			(*n)++;
    		}
    	}
    }
    
    • 1

    Information

    ID
    17546
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By