1 solutions
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0
C :
#include <stdio.h> int main() { int i,j,s; int a[5][3]; for(i=0;i<5;i++) { for(j=0;j<3;j++) scanf("%d",&a[i][j]); } int (*p)[3]; for(i=0; i<5; i++) { p=&a[i]; s=0; for(j=0; j<3; j++) s+=*(*p+j); printf("%d %d",i+1,s); if(i!=4) printf("\n"); } return 0; }
- 1
Information
- ID
- 17535
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By