1 solutions

  • 0
    @ 2025-11-5 16:04:06

    C :

    #include<stdio.h>
    #include<string.h>
    int main()
    {
    	int n,m,a;
    	long long i,j,k;
    	while(~scanf("%d%d%d",&n,&m,&a))
    	{
    		for(i=1;;i++)
    		{
    		  if(a*i>=n)
    		  break;
    		}
    		for(j=1;;j++)
    		{
    		  if(a*j>=m)
    		  break;
    		}
    		k=i*j;
    		printf("%lld\n",k);
    	}
    	return 0;
    }
    

    C++ :

    #include<cstdio>
    #include<iostream>
    #include<cmath>
    
    using namespace std;
    
    int main()
    {
        long long n, m, a;
    //    freopen("in.txt", "r", stdin);
    //    freopen("out_test.txt", "w", stdout);
        while(cin >> n >> m >> a)
        {
            long long tn = (n % a == 0 ? n / a : n / a + 1);
            long long tm = (m % a == 0 ? m / a : m / a + 1);
            cout << tn * tm << endl;
        }
        return 0;
    }
    
    
    • 1

    Information

    ID
    17478
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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