1 solutions
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0
C :
#include<stdio.h> #include<string.h> int main() { int n,m,a; long long i,j,k; while(~scanf("%d%d%d",&n,&m,&a)) { for(i=1;;i++) { if(a*i>=n) break; } for(j=1;;j++) { if(a*j>=m) break; } k=i*j; printf("%lld\n",k); } return 0; }C++ :
#include<cstdio> #include<iostream> #include<cmath> using namespace std; int main() { long long n, m, a; // freopen("in.txt", "r", stdin); // freopen("out_test.txt", "w", stdout); while(cin >> n >> m >> a) { long long tn = (n % a == 0 ? n / a : n / a + 1); long long tm = (m % a == 0 ? m / a : m / a + 1); cout << tn * tm << endl; } return 0; }
- 1
Information
- ID
- 17478
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By