1 solutions
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0
C++ :
#include<iostream> #include<cmath> using namespace std; int main() { int N; cin >> N; int *num = new int[N]; for(int i = 0; i < N; i++) { cin >> num[i]; } for(int k = 0; k < N; k++) { for(int i = 1; i <= num[k]; i++) { for(int j = 1; j <= num[k]; j++) { if(j == num[k]) cout << i*j; else cout << i*j << " "; } cout << endl; } } delete [] num; return 0; }
- 1
Information
- ID
- 17461
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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