1 solutions
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0
C :
#include"stdio.h" int main() { int n,i,m,sum=0; while(scanf("%d",&n)!=EOF) { sum=0; if(n!=0) {for(i=0;i<n;i++) {scanf("%d",&m); sum=sum+m;} printf("%d\n",sum);} else break; } return 0; }Pascal :
var a:array[1..100000] of longint; i,n,x,p,j:longint; begin for i:=1 to 100000 do begin read(n); if not(n=0) then begin for j:=1 to n do begin read(x); a[i]:=a[i]+x; end; end else begin p:=i-1; break; end; end; for i:=1 to p do writeln(a[i]); end.
- 1
Information
- ID
- 17369
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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