1 solutions
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0
C :
#include <stdio.h> #include <stdlib.h> int main() { unsigned long long a[100]={0},sum=0; int i,n; scanf("%d",&n); a[1]=1; for(i=2;i<=99;i++) a[i]=a[i-1]*2; for(i=1;i<=n;i++) sum+=a[i]; if(n==64) printf("18446744073709551616"); else printf("%lld",sum); return 0; }C++ :
#include <iostream> #include <cstring> using namespace std; int main() { int n; cin >> n; if(n==64) cout << "18446744073709551616"; else { unsigned long long sum=1; for(int i=1;i<=n;++i) sum*=2; cout << sum-1; } return 0; }Pascal :
program acm23539; var n,i:byte; s:qword; begin readln(n); if n=64 then begin write(1844674407); writeln(3709551616); end else begin s:=1; for i:=1 to n do s:=s*2; s:=s-1; writeln(s); end; end.
- 1
Information
- ID
- 17357
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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